Everyone can see the chart, but only a few can actually read it.
- Post #961,121
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- Feb 18, 2015 10:16am Feb 18, 2015 10:16am
- Joined May 2014 | Status: From1toMillion | 9,012 Posts
- Post #961,122
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- Feb 18, 2015 10:16am Feb 18, 2015 10:16am
- | Commercial Member | Joined Oct 2012 | 3,968 Posts
- Post #961,123
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- Feb 18, 2015 10:19am Feb 18, 2015 10:19am
- | Joined Oct 2009 | Status: Member | 371 Posts
- Post #961,124
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- Feb 18, 2015 10:19am Feb 18, 2015 10:19am
- | Commercial Member | Joined Oct 2012 | 3,968 Posts
- Post #961,125
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- Feb 18, 2015 10:22am Feb 18, 2015 10:22am
- | Joined Jul 2009 | Status: naughty | 915 Posts
----- Dragonfly out in the sun you know what I mean, don't you know
- Post #961,126
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- Feb 18, 2015 10:24am Feb 18, 2015 10:24am
- | Joined Oct 2009 | Status: Member | 371 Posts
- Post #961,127
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- Feb 18, 2015 10:25am Feb 18, 2015 10:25am
- Joined Apr 2014 | Status: Member | 1,094 Posts
- Post #961,128
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- Joined Mar 2012 | Status: Member | 2,310 Posts
- Post #961,129
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- Feb 18, 2015 10:27am Feb 18, 2015 10:27am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c
- Post #961,130
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- Feb 18, 2015 10:28am Feb 18, 2015 10:28am
- Joined Mar 2012 | Status: Member | 2,310 Posts
- Post #961,131
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- Feb 18, 2015 10:30am Feb 18, 2015 10:30am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c
- Post #961,132
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- Feb 18, 2015 10:32am Feb 18, 2015 10:32am
- Joined Apr 2014 | Status: Member | 1,094 Posts
- Post #961,133
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- Feb 18, 2015 10:32am Feb 18, 2015 10:32am
- Joined Mar 2010 | Status: Technical Fundamentalist | 11,563 Posts
Pending conversations? PM for a chat...I am mainly in OTM now
- Post #961,134
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- Feb 18, 2015 10:33am Feb 18, 2015 10:33am
- | Commercial Member | Joined Oct 2012 | 3,968 Posts
- Post #961,135
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- Feb 18, 2015 10:34am Feb 18, 2015 10:34am
- Joined Mar 2012 | Status: Member | 2,310 Posts
- Post #961,136
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- Feb 18, 2015 10:34am Feb 18, 2015 10:34am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c
- Post #961,137
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- Feb 18, 2015 10:35am Feb 18, 2015 10:35am
- | Commercial Member | Joined Oct 2012 | 3,968 Posts
- Post #961,138
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- Feb 18, 2015 10:35am Feb 18, 2015 10:35am
- Joined Apr 2014 | Status: Member | 1,094 Posts
- Post #961,139
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- Feb 18, 2015 10:37am Feb 18, 2015 10:37am
- | Joined Oct 2009 | Status: Member | 371 Posts
- Post #961,140
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- Feb 18, 2015 10:37am Feb 18, 2015 10:37am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c