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- Jan 20, 2015 1:28am Jan 20, 2015 1:28am
- | Joined Nov 2014 | Status: Member | 176 Posts
- Post #951,942
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- Jan 20, 2015 1:30am Jan 20, 2015 1:30am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c
- Post #951,943
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- Jan 20, 2015 1:31am Jan 20, 2015 1:31am
- | Joined Nov 2014 | Status: Member | 176 Posts
- Post #951,944
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- | Joined Nov 2014 | Status: Member | 176 Posts
- Post #951,945
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- Jan 20, 2015 1:37am Jan 20, 2015 1:37am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c
- Post #951,946
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- Jan 20, 2015 1:43am Jan 20, 2015 1:43am
- Joined Jun 2010 | Status: Hello,Mr.Market | 1,805 Posts
A chart helps those who can read it.
- Post #951,947
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- | Joined Nov 2014 | Status: Member | 176 Posts
- Post #951,948
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- Jan 20, 2015 1:59am Jan 20, 2015 1:59am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c
- Post #951,951
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- Jan 20, 2015 2:52am Jan 20, 2015 2:52am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c
- Post #951,954
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- Jan 20, 2015 3:12am Jan 20, 2015 3:12am
- Joined Jan 2010 | Status: Member | 11,001 Posts
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- Joined Jan 2010 | Status: Member | 11,001 Posts
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- | Joined Dec 2014 | Status: Member | 503 Posts
- Post #951,960
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- Jan 20, 2015 4:02am Jan 20, 2015 4:02am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c