- Post #869,641
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- Jan 13, 2014 10:00am Jan 13, 2014 10:00am
- Joined Jun 2013 | Status: Trader by hobby not by profession | 6,132 Posts
- Post #869,642
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- Jan 13, 2014 10:01am Jan 13, 2014 10:01am
- Joined Jun 2013 | Status: Trader by hobby not by profession | 6,132 Posts
- Post #869,643
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- Jan 13, 2014 10:02am Jan 13, 2014 10:02am
- | Joined Aug 2013 | Status: Member | 986 Posts
- Post #869,644
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- Jan 13, 2014 10:03am Jan 13, 2014 10:03am
- | Joined May 2010 | Status: Member | 2,442 Posts
- Post #869,645
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- Jan 13, 2014 10:10am Jan 13, 2014 10:10am
- Joined Jun 2013 | Status: Trader by hobby not by profession | 6,132 Posts
- Post #869,646
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- Jan 13, 2014 10:12am Jan 13, 2014 10:12am
- | Membership Revoked | Joined May 2013 | 7,946 Posts
ignore wackos and psychos, including myself. But I can't add myself to iggy
- Post #869,647
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- Jan 13, 2014 10:12am Jan 13, 2014 10:12am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c
- Post #869,648
- Quote
- Jan 13, 2014 10:13am Jan 13, 2014 10:13am
- | Membership Revoked | Joined May 2013 | 7,946 Posts
ignore wackos and psychos, including myself. But I can't add myself to iggy
- Post #869,649
- Quote
- Jan 13, 2014 10:16am Jan 13, 2014 10:16am
- | Membership Revoked | Joined May 2013 | 7,946 Posts
ignore wackos and psychos, including myself. But I can't add myself to iggy
- Post #869,650
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- Jan 13, 2014 10:19am Jan 13, 2014 10:19am
- | Membership Revoked | Joined Jun 2011 | 2,124 Posts
fokyou forexfactory
- Post #869,651
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- Jan 13, 2014 10:22am Jan 13, 2014 10:22am
- Joined Jan 2010 | Status: No Hope for FF | 3,772 Posts
@pawpaw1000 on Twitter
- Post #869,654
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- Jan 13, 2014 10:26am Jan 13, 2014 10:26am
- | Joined Aug 2013 | Status: Member | 986 Posts
- Post #869,655
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- Edited 10:41am Jan 13, 2014 10:29am | Edited 10:41am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c
- Post #869,657
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- Jan 13, 2014 10:31am Jan 13, 2014 10:31am
- | Membership Revoked | Joined Mar 2009 | 16,693 Posts
- Post #869,658
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- Jan 13, 2014 10:54am Jan 13, 2014 10:54am
- | Joined Mar 2010 | Status: Member | 499 Posts
- Post #869,659
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- Jan 13, 2014 10:55am Jan 13, 2014 10:55am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c
- Post #869,660
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- Edited 11:24am Jan 13, 2014 11:00am | Edited 11:24am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c