Disliked{quote} Correct. Good job. Answer: This is a typical algebra problem with two unknowns, and we need to have two equations to solve the problem. LetXbe the number of cows, andYthe number of chickens. The number of cows plus the number of chickens equals 30: X + Y = 30 Since cows have four legs and chickens have two legs, we can also have an equation for the number of legs. 4 X + 2 Y = 74 Rearranging the first equation we get X = 30 - Y Substituting X in the second equation gives us 4 × (30 - Y) + 2 Y = 74 120 - 4 Y + 2 Y = 74 -2 Y = 74 - 120 = -46...Ignored
74-4 = If divisible by 2 ok, if not repeat and rinse until you get a figure that is divisible by 2. But more than one answers are possible.
The Thief of Wall Street
But you should have said "Total 30 legged living organisms" instead of "30 animals" for those who don't know or are too lazy to do the math & trying to figure out some excuses..
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