# Line slope calculator 10x+y=90

**Straight line given by points A[8; 10] and B[9; 0]**

## Calculation:

**Slope-intercept form of line:**y = -10x+90

**Canonical form of the line equation:**10x+y-90 = 0

**Parametric form of the line equation:**

x = t+8

y = -10t+10 ; t ∈ R

**Slope:**m = -10

**Slope angle of line: φ =**-84°17'22″ = -1.4711 rad

**X intercept:**x

_{0}= 9

**Y intercept:**y

_{0}= q = 90

**Distance line from the origin:**d

_{0}= 8.9553

**The length of the segment AB: |AB| =**10.0499

**Vector: AB =**(1; -10)

**Normal vector: n =**(10; 1)

**Midpoint of the segment AB: M =**[8.5; 5]

**Perpendicular Bisector equation:**x-10y+41.5 = 0

**Vector OA = (8; 10) ; |OA| = 12.8062**

**Vector OB = (9; 0) ; |OB| = 9**

**Scalar product OA .OB = 72**

**Angle ∠ AOB = 51°20'25″ = 0.8961 rad**