Maths question and MT4 compiler/tester issue?

Quoting ramzam

Disliked

is it missing + (a+c)/2 +(b+d)/2 +(e+g)/2 +(f+h)/2

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Quoting Pipologist

Disliked

This is a two part question. The first is a simple math question that I'd like to get some input on. 1) What is the lowest common denominator of this formula? Or, how to distill the formula down to the simplest formula without altering the final calculation? Forgive the strange formatting, basically it's a combination of 8 variables (A - H) divided by 20. X = ( (A + B)/2 + (C + D)/2 + (E + F)/2 + (G + H)/2 + (A + B)/2 + (C + D)/2 + (E + F)/2 + (G + H)/2 + (A + D)/2 + (B + C)/2 + (A + F)/2 + (B + E)/2 + (A + H)/2 + (B + G)/2 + (C + F)/2 + (D + E)/2...

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Quoting tradability

Disliked

{quote} There shouldn't be a difference at all. You must have left something out that you're not showing us.

Ignored

Quoting FxChristo

Disliked

(A + B)/2 = A/2 + B/2 Therefore: X = ( 2.5*A + 2.5*B + 2.5*C + 2.5*D + 2.5*E + 2.5*F + 2.5*G + 2.5*H) / 20

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Quoting tradability

Disliked

{quote} There's a more efficient way and that is to take out all the denominators like this ... /40 rather than dividing by 20.

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Quoting FxChristo

Disliked

{quote} 2.5/20 = 0.125 so It's actually X = 0.125 * (A + ... + H)

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Quoting tradability

Disliked

{quote} That's true but it isn't the most efficient way, having the common denominator is the most efficient way for a PC, perhaps in our minds it is we are doing most of the calculation. Let machines do the work and save your thinking energy to work for me trading lol

Ignored

X = (A + B)/2 + (C + D)/2 + (E + F)/2 + (G + H)/2 +
       (A + B)/2 + (C + D)/2 + (E + F)/2 + (G + H)/2 +
       (A + D)/2 + (B + C)/2 + (E + H)/2 + (F + G)/2 +
       (A + F)/2 + (B + E)/2 + (A + H)/2 + (B + G)/2 +
       (C + F)/2 + (D + E)/2 + (C + H)/2 + (D + G)/2
= 1/2 * 1/20 * (A + B + C + D + E + F + G + H + A +
    B + C + D + E + F + G + H + A + D +
    B + C + E + H + F + G + A + F + B +
    E + A + H + B + G + C + F + D + E +
    C + H + D + G )
= 1/40 * (A + B + C + D + E + F + G + H + A +
    B + C + D + E + F + G + H + A + D +
    B + C + E + H + F + G + A + F + B +
    E + A + H + B + G + C + F + D + E +
    C + H + D + G )
= 1/40 * (5*A + 5*B + 5*C + 5*D +
    5* E + 5* F + 5* G + 5*H)
= 5/40 * (A + B + C + D + E + F + G + H)
= 1/8 * (A + B + C + D + E + F + G + H)
= 0.125 * (A + B + C + D + E + F + G + H)

Quoting 9047

Disliked

{quote} FXChristo is on the money. Multiplication and division are expensive operations compared to addition and subtraction. As they have stated the formula reduces to: X = (A + B)/2 + (C + D)/2 + (E + F)/2 + (G + H)/2 + (A + B)/2 + (C + D)/2 + (E + F)/2 + (G + H)/2 + (A + D)/2 + (B + C)/2 + (E + H)/2 + (F + G)/2 + (A + F)/2 + (B + E)/2 + (A + H)/2 + (B + G)/2 + (C + F)/2 + (D + E)/2 + (C + H)/2 + (D + G)/2 = 1/2 * 1/20 * (A + B + C + D + E + F + G + H + A + B + C + D + E + F + G + H + A + D + B + C + E + H + F + G + A + F + B + E + A + H + B +...

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Quoting tradability

Disliked

{quote} It seems your lack of understanding is bad... I didnt say FXChristo was wrong and your maths must be pathetic to not understand that he did all the calculations rather than the program doint it. Perhaps your level of understanding is like his. lol Anyone could have done the calculations and even found the final answer which means there was no need for a program to do it doh

Ignored

Quoting 9047

Disliked

{quote} Apologies I didn't mean to hit quote on your reply .... I just meant to reply to the thread. Optimising equations before implementation in code is always good practice. Sure in this instance it doesn't save much as you would expect the compiler to optimise this (if its half decent). But can you explain why my math is "pathetic" ?

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Quoting tradability

Disliked

{quote} Because you missed my point so for a good mathematician one reads and understands the theory behind it before answering. But if you think you can teach me about maths I right here at any level! The bottom line is not whether there is a simpler way, what was asked was "is there anything wrong" with his final equation, which there isn't.

Ignored

Quoting Pipologist

Disliked

This is a two part question. The first is a simple math question that I'd like to get some input on. 1) What is the lowest common denominator of this formula? Or, how to distill the formula down to the simplest formula without altering the final calculation? Forgive the strange formatting, basically it's a combination of 8 variables (A - H) divided by 20. X = ( (A + B)/2 + (C + D)/2 + (E + F)/2 + (G + H)/2 + (A + B)/2 + (C + D)/2 + (E + F)/2 + (G + H)/2 + (A + D)/2 + (B + C)/2 + (A + F)/2 + (B + E)/2 + (A + H)/2 + (B + G)/2 + (C + F)/2 + (D + E)/2...

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//+------------------------------------------------------------------+
//|                                         pipologist_equations.mq4 |
//|                                              http://ninety47.com |
//+------------------------------------------------------------------+
#property copyright "Opensource"
#property link      "http://ninety47.com"
#property version   "1.00"
#property strict
 
void OnStart() {
    double X1, X2, X3;
    double A = 1.0,
           B = 2.0,
           C = 3.0,
           D = 4.0,
           E = 5.0,
           F = 6.0,
           G = 7.0,
           H = 8.0;
    
    X1 = (
        (A + B)/2
        + (C + D)/2
        + (E + F)/2
        + (G + H)/2
        + (A + B)/2
        + (C + D)/2
        + (E + F)/2
        + (G + H)/2
        + (A + D)/2 + (B + C)/2
        + (A + F)/2 + (B + E)/2
        + (A + H)/2 + (B + G)/2
        + (C + F)/2 + (D + E)/2
        + (C + H)/2 + (D + G)/2
        + (E + H)/2 + (F + G)/2
        ) / 20;
 
    X2 = (
        (A + B)/2
        + (C + D)/2
        + (E + F)/2
        + (G + H)/2
        + (A + B)/2
        + (C + D)/2
        + (E + F)/2
        + (G + H)/2
        + (A + D)/2 + (B + C)/2
        + (E + H)/2 + (F + G)/2
        + (A + F)/2 + (B + E)/2
        + (A + H)/2 + (B + G)/2
        + (C + F)/2 + (D + E)/2
        + (C + H)/2 + (D + G)/2
        ) / 20;  
        
    X3 = 0.125 * (A + B + C + D + E + F + G + H);
            
    Print("X1 = ", DoubleToStr(X1,3), ", X2 = ", DoubleToStr(X2, 3), " X3 = ", DoubleToStr(X3, 3));        
}
//+------------------------------------------------------------------+

Quoting 9047

Disliked

{quote} So what your saying is you've got nothing but snipes and jibes. Good work. Park your ego and lets leave this weird bickering and angst here and get the thread back on topic. EDIT: If you feel the need to have a bash please do it on a PM Then I'll buy you a beer and we move on.

Ignored

Quoting tradability

Disliked

{quote} No what I'm saying is fools and tools float everywhere

Ignored