Well, we will wait for GG and Carl
- #122
- Jan 9, 2014 9:18am Jan 9, 2014 9:18am
@ gg53
I must be doing something wrong.
capture introduce and comment:
1 - start to calculate from the red vertical line
2 - introduce fractal pattern [1] and according to probability, this pattern is correct
3 - in a length L = 5 bars gives me high probability in length with fractal pattern [1]
4 - step to determine "next bar" and "Current bar" and both give me 100% bearish, so I put bearish signal.
5 - Loop calculating from this signal, but this time looking bullish signal.
6 - In conclusion, where the second red arrow is where I appear bullish signal.
When will it mean "prediction error" is to these cases?
I must be doing something wrong.
capture introduce and comment:
1 - start to calculate from the red vertical line
2 - introduce fractal pattern [1] and according to probability, this pattern is correct
3 - in a length L = 5 bars gives me high probability in length with fractal pattern [1]
4 - step to determine "next bar" and "Current bar" and both give me 100% bearish, so I put bearish signal.
5 - Loop calculating from this signal, but this time looking bullish signal.
6 - In conclusion, where the second red arrow is where I appear bullish signal.
When will it mean "prediction error" is to these cases?
- #130
- Jan 10, 2014 5:04am Jan 10, 2014 5:04am
Gg53 thank you very much for your reply.
Regarding your explanation, there have been several questions that have to do with the calculation process.
I'll catch up first:
I'll catch up a first calculation process and this leg zigzag like me might correct me on the steps performed poorly.
Top starting here. We have a confirmed zzbottom and seek zzup.
We do not have any fractal therefore expect more candles.
Fractals have not yet, so we are still waiting
Fractals have not yet, so we are still waiting
A fractal appears therefore introduce [1] algorithm and begin to calculate probabilities. Counted a length of 8. Calculating the probabilities are accepted and we calculate probability “next bar” and failed
A fractal appears therefore introduce [1] algorithm and begin to calculate probabilities. Counted a length of 9. Calculating the probabilities are accepted and we calculate probability “next bar” and failed
A fractal appears therefore introduce [1] algorithm and begin to calculate probabilities. Counted a length of 10. Calculating the probabilities are accepted and we calculate probability “next bar” and failed
A new fractal appears, and we introduce in algorithm [1 0] with length 11. When we study the probability of pattern fractal, we have more probability in patten [1 0 1]. We look at bars until in length ( 11-3 =8 ) and the algorithm say us that the pattern [1 0 1] is more likely. Therefore, we hope to next fractal.
Appears fractal and zz. We introduce in the algorithm pattern [1 0 1] and length 14.
By studying "next bar" is failed.
Continuous calculated the following 3 candles but dont give me signal of swing.
Thus the correct way ? i will more questions later because i dont want to collapse the thread.
Many thanks
Regarding your explanation, there have been several questions that have to do with the calculation process.
I'll catch up first:
I'll catch up a first calculation process and this leg zigzag like me might correct me on the steps performed poorly.
Top starting here. We have a confirmed zzbottom and seek zzup.
We do not have any fractal therefore expect more candles.
Fractals have not yet, so we are still waiting
Fractals have not yet, so we are still waiting
A fractal appears therefore introduce [1] algorithm and begin to calculate probabilities. Counted a length of 8. Calculating the probabilities are accepted and we calculate probability “next bar” and failed
A fractal appears therefore introduce [1] algorithm and begin to calculate probabilities. Counted a length of 9. Calculating the probabilities are accepted and we calculate probability “next bar” and failed
A fractal appears therefore introduce [1] algorithm and begin to calculate probabilities. Counted a length of 10. Calculating the probabilities are accepted and we calculate probability “next bar” and failed
A new fractal appears, and we introduce in algorithm [1 0] with length 11. When we study the probability of pattern fractal, we have more probability in patten [1 0 1]. We look at bars until in length ( 11-3 =8 ) and the algorithm say us that the pattern [1 0 1] is more likely. Therefore, we hope to next fractal.
Appears fractal and zz. We introduce in the algorithm pattern [1 0 1] and length 14.
By studying "next bar" is failed.
Continuous calculated the following 3 candles but dont give me signal of swing.
Thus the correct way ? i will more questions later because i dont want to collapse the thread.
Many thanks
{quote}A few anxious moments for me at first, but after looking everything through I realized I had already done everything the same as you. One thing though - the section of comparing fractal pattern occurrences. Which is the correct way, is it current > 1 && current > 0 or current > 1+0? Both versions float around, would be good to specify which is the one. Thanks! C.
My algorithm has not evolved enough to catch all the "swing points" yet...
current > "1" && current > "0"
Thanks.
- #138
- Jan 10, 2014 9:28am Jan 10, 2014 9:28am
{quote} I am handling 2 fractals in one bar the following way... G says whatever comes first, the bottom or the top, and that should be the order. So, if I have a bullish bar with 2 fractals, I can logically assume that the bottom fractal came first, since the close of the bar is higher than the open. If I have a bearish bar with 2 fractals, I can logically assume that the top fractal came first. That may not be in 100% of the cases, but it is fairly rare, so I'm not to worried about it, so I will stick with my logical, most probable method. If...
{quote} If you really want to know for all 100% of the cases, you would have to drop down to the 1-min chart. Carl
Thanks Carl.
-smallcat
- #140
- Jan 10, 2014 9:56am Jan 10, 2014 9:56am
- Joined Feb 2009 | Status: Half in the Bag | 17,827 Posts
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