- #19,454
- Jun 17, 2015 12:16pm Jun 17, 2015 12:16pm
- Joined Dec 2013 | Status: Trader | 2,141 Posts
f(z)=z2+c
- #19,456
- Jun 17, 2015 2:56pm Jun 17, 2015 2:56pm
- Joined Dec 2013 | Status: Trader | 2,141 Posts
f(z)=z2+c
- #19,457
- Jun 18, 2015 4:32pm Jun 18, 2015 4:32pm
- Joined Jun 2011 | Status: the risk is the unknown | 2,182 Posts