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Sine Wave and Channel Reflection, Action/Reaction putting it all together

  • #121
  • May 5, 2013 12:31pm May 5, 2013 12:31pm
QUESTION:

Are all lines such as these equal in length within a square?
Attached Image (click to enlarge)
Click to Enlarge Name: SQUARE.GIF Size: 23 KB
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
  • #122
  • May 5, 2013 5:59pm May 5, 2013 5:59pm
Quoting kapital
I'm not necessarily seeking an equation. I'm basically seeking a way (on the chart) to make AB equal the length of CD or CD equal the length of AB. In the end, I wish to keep the angle of orientation the same. Your placing the two lines together sparked something in my mind. I''ll try it out and get back with ya. {image} {image}

I'm trying to understand your logic as defined by your chart..... what is the relationship between AB and CD? I know you're trying to find a method for squaring the two but why? In the past I've looked into equal relationships defined by price action like simple measured moves, or more complex, trying to square the time price stays in a range to the following distance of it's breakout..,,,, but here I'm at a loss.
Attached Image
  • #123
  • May 5, 2013 6:10pm May 5, 2013 6:10pm
Quoting kapital
QUESTION: Are all lines such as these equal in length within a square? {image}
Kap you've lost me
  • #124
  • May 5, 2013 6:49pm May 5, 2013 6:49pm
Quoting auxesis
{quote} I'm trying to understand your logic as defined by your chart..... what is the relationship between AB and CD? I know you're trying to find a method for squaring the two but why? In the past I've looked into equal relationships defined by price action like simple measured moves, or more complex, trying to square the time price stays in a range to the following distance of it's breakout..,,,, but here I'm at a loss. {image}
"Why" doesn't even have a seat at the table for the time being. This is something I've pondered over for quite some time. I decided the other day to just "go at it" and figure it out.

Forget price action and the markets and just focus on the lines. If you had to do what I've been asking, how would you do it?

I see how difficult a task it is if "Auxesis The Great" is having a difficult time with it.
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
  • #125
  • May 5, 2013 7:28pm May 5, 2013 7:28pm
Quoting auxesis
{quote} Kap you've lost me
Question 1

Since all sides of a square are equal, would all lines drawn from any corner to either of the two opposite perimeters be equal in length?


Question 2: How would you convert a rectangle into a square?

The answers to these questions should take us a step closer to solving this mystery.

I have a feeling the answer is so simple and is right under our noses.
Attached Image (click to enlarge)
Click to Enlarge Name: SQUARES.GIF Size: 28 KB
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
  • #126
  • May 5, 2013 7:38pm May 5, 2013 7:38pm
It just dawned on me that I can actually measure the length of lines in a chart.

So, if an equation exists for this then by all means share it. However, even if it does exist, I still would like to derive the answer by means of using just lines on the chart as opposed to using an equation.
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
  • #127
  • Edited 11:37pm May 5, 2013 10:16pm | Edited 11:37pm
Quoting kapital
{quote} "Why" doesn't even have a seat at the table for the time being. This is something I've pondered over for quite some time. I decided the other day to just "go at it" and figure it out. Forget price action and the markets and just focus on the lines. If you had to do what I've been asking, how would you do it? I see how difficult a task it is if "Auxesis The Great" is having a difficult time with it.
Kap,

Please no "Auxesis the Great" stuff,, there's nothing special here.......... you want to make two lines of unequal length on a chart, equal each other... they don't unless you're introducing something else into the equation; time for example. I though maybe if you thought of a line on a chart via a spherical coordinate system, x,y and z axis, changing your frame of reference might help with the answer.

I don't know, I'll mull it over and get back with you.
  • #128
  • May 6, 2013 4:04am May 6, 2013 4:04am
How about "The Great Auxesis"? LOL....just kidding.

Allow me to show what I've been working on. It doesn't appear to provide the solution I am looking for. Some lines in the last chart appear longer than others.

However, I'm looking into something else along these lines.
Attached Image(s) (click to enlarge)
Click to Enlarge Name: SQUARING 1.GIF Size: 17 KB
Click to Enlarge Name: SQUARING 2.GIF Size: 17 KB
Click to Enlarge Name: SQUARING 3.GIF Size: 18 KB
Click to Enlarge Name: SQUARING 4.GIF Size: 26 KB
Click to Enlarge Name: SQUARING 5.GIF Size: 26 KB
Click to Enlarge Name: SQUARING 6.GIF Size: 22 KB
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
  • #129
  • May 7, 2013 4:39am May 7, 2013 4:39am
Kap,

Interesting stuff. I remember looking into similar moons ago, some study friends were toying with the idea of lines of force originating from points other than just a major significant high or low, similar to Micheal Jenkins, zero line angles...... we even had fib spirals starting from selected open spaces
on the chart trying to line up with the rhythms catching the turns...... My old brain looks for simplicity there days.

Keep thinking outside the box.

regards
  • #130
  • May 8, 2013 1:39am May 8, 2013 1:39am
Quoting kapital
Some lines in the last chart appear longer than others....
Excuse me for butting in, but I don't follow your logic. Given that the side of a square is equal to a radius that connects adjacent corners of the square, how can any line originating from that point and projected to an opposing side, be of the same length...unless you are considering in 3D instead of 2D?

Attached Image (click to enlarge)
Click to Enlarge Name: dimetric.jpg Size: 305 KB



It looks to me as though you are dimetrically projecting a square, which is a little tricky in MT4....
  • #131
  • May 8, 2013 2:56pm May 8, 2013 2:56pm
Quoting One day!
{quote} Excuse me for butting in, but I don't follow your logic. Given that the side of a square is equal to a radius that connects adjacent corners of the square, how can any line originating from that point and projected to an opposing side, be of the same length...unless you are considering in 3D instead of 2D? {image} It looks to me as though you are dimetrically projecting a square, which is a little tricky in MT4....
No problem One day....keep butting in.

I was unaware that the radius was equal to a side. I'm not too brushed up on my geometry so I'm doing most of this through trial and error. However, I did eventually discover that the lines would not turn out equal the way I was doing it.

With that said, do you have any insight into how to make one line equal to another of different orientation?
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
  • #132
  • May 9, 2013 5:22am May 9, 2013 5:22am
Quoting kapital
{quote} ....do you have any insight into how to make one line equal to another of different orientation?
If you think of the lines as radii within a unit circle/ sphere, then they will have the same length....


Attached Image


Line a and b are equal. They are still equal in the image below as they still emanate from the centre and project to the surface of the sphere....

Attached Image


They are still equal even when rotated and appear to be different lengths....

Attached Image


So they are both parts of right triangles within the sphere, which means that you can use trigonometry. Does that help at all?...

Regards

OD
  • #133
  • May 9, 2013 2:42pm May 9, 2013 2:42pm
Thanks for the reply One Day. You have given me food for thought.

Did you produce the images in your post yourself? If so, what software did you use?
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
  • #134
  • May 10, 2013 3:51am May 10, 2013 3:51am
Quoting kapital
Thanks for the reply One Day. You have given me food for thought. Did you produce the images in your post yourself? If so, what software did you use?
Hi Kap'

I used Calques 3D to create the sphere, which you can find here: http://www.calques3d.org/ - it is free to download.

For additional annotation, I used PicPick, which is free for home use - http://www.picpick.org/en/download_free
  • #135
  • May 11, 2013 3:40pm May 11, 2013 3:40pm
Thanks again One Day!
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
  • #136
  • Sep 18, 2013 5:23pm Sep 18, 2013 5:23pm
Nice swing reflection coupled with pitchfork:

http://oi40.tinypic.com/6gew3q.jpg
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
  • #137
  • Edited 8:59pm Sep 18, 2013 8:13pm | Edited 8:59pm
If the median line is the target, expect more upward movement.

The chart shows what I have called a reflective pitchfork. It is a fork where the slope of the baseline is equal to, but opposite, the slope of the lines of the pitchfork.
Attached Image (click to enlarge)
Click to Enlarge Name: GU.png Size: 80 KB
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
  • #138
  • Sep 18, 2013 8:18pm Sep 18, 2013 8:18pm
Here is a traditional pitchfork in play using the extreme low as the C pivot:
Attached Image (click to enlarge)
Click to Enlarge Name: GU2.png Size: 75 KB
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
  • #139
  • Sep 18, 2013 8:22pm Sep 18, 2013 8:22pm
Here is what the reflective pitchfork would have looked like if I had used the extreme low as the C pivot:
Attached Image (click to enlarge)
Click to Enlarge Name: GU REFLECTIVE.png Size: 77 KB
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
  • #140
  • Sep 23, 2013 7:05am Sep 23, 2013 7:05am
Awaiting price to reach the reflective line:
Attached Image (click to enlarge)
Click to Enlarge Name: REFLECTION 16.png Size: 49 KB
"GIVE ME 3 POINTS IN SPACE IN TIME AND WATCH ME CREATE MAGIC."
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