Sine Wave and Channel Reflection, Action/Reaction putting it all together

Throwing in a few additional lines:

...

The concept behind the reverse/flip pitchfork:

Greetings,

I need help in finding out how to make a (diagonal) line equal in length to another one with a different orientation.

Kap,

On the fly this morning, no time.... Think about Newtons law on motion and Your basic geometry, hope that steers you in the right direction. I'll check back later

LAW III To every action there is always opposed an equal reaction: or, the mutual actions of two bodies upon each other are always equal, and directed to contrary parts.

I'm still at a roadblock....I need for ya to clear the way.

Kap,

Try looking at the problem using a 3D perspective, pull out your old analytical geometry notes from school, assuming the two lengths are the same, think isosceles triangle, then what orientation would you have to view it from to match.

The Pitchfork is working along the same concept..... imagine a line from p0 to p3...... the move away from that line that forms p1 is matched going the opposite direction to p2..... like a sine wave..... naturally the waves completes ina return to that original line back at p3.

Apologies for the time constraints here,

a

edit; in the triangle your assuming that y is the reflection point..... the action going into it is reflected into an equal reaction forming the two equal sides of the shape. if it's equilateral y=x which may not be the case. you can also try solving the problem assuming y forms a 90' making it a right triangle... that limits your possibilities but makes the math easier...... imho it's more complex than that.

edit; if the orientation is perpendicular to the triangle, it would appear as if we were looking down onto it, move that orientation and the the shape of the triangle and lengths of the lines change.... those points on a sphere that mark the orentation should be able to be calculated.

I ain't gonna lie...that confused the hell out of me. (lol)

A reverse fork at work on the hourly EUR/USD:

Good resonance found in this setup...

The circles are target areas for price.

If price doesn't hold where it currently is, then I'm looking for a drop to the area circled at the bottom.

A strong push to the upside would prove difficult as of now.

I guess the euro had a lil' gas in the take....up 40+ pips.

More like a full tank!

Like the reflection

You are doing Great work Kapital. Congratulations on thinking outside the box and developing your own style, nicely done!

sjc

Thanks for the comments guys. I decided to clean things up a bit and make a few adjustments.

Auxesis, I thank you for the explanation you gave above. However, I need an exact demonstration to make it crystal clear for me.

Remember, the aim is to make one line equal in length to another when they are of different lengths, slope, and direction.

Kap,

I may have jumped the gun assuming we are talking about the same concept, but are you looking for an equation? I was trying to point you in a direction to demonstrate the concept, but first you have to conclude the markets are 3 dimensional if your talking orientation.....I'm assuming your trying to square the distances of two waves or price movements of different lengths?

You can take the Gannish approach for squaring time/price, I'd suggest an author Bryce Gilmore, "Geometry of Markets" a bare bones approach on the subject. The other is Bradley Cowan, he deals with what he calls 4 dimensional market structures... get ready for a brain melt.

back to the topic of conversation.... let's make sure we are talking about what i think we are talking about. you're looking for a way to square the two distances AB=BC, specifically in relation to the angle of orientation? For this discussion it is given that AB=BC but because we are viewing from an orientation that is not perpendicular, i.e. straight up and down, the most distant segment, here AB seems shorter?

Edit; for example, I'm sitting here at my desk holding a square post-it note. When I look straight down at the post-it note all sides are the same length, but if I hold it up and turn my hand looking across it, the closer my view or orientation gets to parallel then the sides appear to be different lengths. Is this where we are headed, I see a potential problem ahead for you, to be leading you have to know in advance your angle of orientation and structure to make a play on "C' unless you're using a predefined criteria.... i.e. Gannish where the relation between the two is some type of time/price squaring. Once "C" is known then we can look for reflective opportunities much like what you've done in your earlier posts. There's usually other considerations in the equation besides just AB and BC

I guess if you have some actual chart snags showing what you're looking for and what you're trying to do?

As for the earlier mention of the pitchfork in regards to orientation, the viewing orientation of price is already figured into it's construction. Instead of squaring AB=CD your squaring the second half of a sine-wave, regardless of the viewing angle, (if you're considering the market as 3 dimensional) the first part of the wave AB, or p0 to p1... will me mirrored in CD or p2 to p3.

I'm not necessarily seeking an equation. I'm basically seeking a way (on the chart) to make AB equal the length of CD or CD equal the length of AB. In the end, I wish to keep the angle of orientation the same.

Your placing the two lines together sparked something in my mind. I''ll try it out and get back with ya.