Coder Question: High value BBand | Forex Factory

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Coder Question: High value BBand

  • #1
  • First Post: Jun 25, 2012 11:41am Jun 25, 2012 11:41am
Hello. I want to ask if someone can assist me on the following issue.

I am using the following code to identify the highest of the past five 1hour bars:

Inserted Code
H1High=High[iHighest(NULL,60,MODE_HIGH,5,1)];

This is all fine. What I would like to accomplish, as well, is to find to the value of the upper Boilinger Band on H1, at the hour of the highest price.

Any help or inputs will be much appreciated, Thanks

Oddvin
  • #2
  • Jun 25, 2012 8:55pm Jun 25, 2012 8:55pm
Quoting enterfx
Inserted Code
H1High=High[iHighest(NULL,60,MODE_HIGH,5,1)];
my approach to something like this would be to use the long version to code this, ie, dont use the High and the iHighest functionality, but instead write it out long hand.

Inserted Code
 
//identify the highest of the past five 1hour bars
int highbar=0;
double highbarval=Close[0];
 
for(bar=0;bar<5;bar++)
{
if(Close[bar]>highbarval) {highbarval=Close[bar]; highbar=bar;}
}/*termination of for loop*/
 
 
/*
now, at this stage we have two variables that are ready for use...
 
highbar: contains a number between 0 and 4.
highbarval: contains the close price of the bar at highbar.
 
now it is fairly simple to read the bollinger band value for bar # highbar.
 
i suspect that the ibands function is what you are looking for..
 
*/

if you require further assistance, please ask.

as i have written the above sample, you will need to run this on a chart that is set to one hour timeframe.

to make the above sample more bulletproof, we would take the effort to record the values for five hours into an array and that way we are also more confident in the values that we are analyzing.

jimmie beans
  • #3
  • Jun 25, 2012 8:57pm Jun 25, 2012 8:57pm
I guess nobody feels like taking this one, so I will.

I am not going to produce working code, but rather explain how to approach the problem.

Right now you have the High value you desire. In order to get the BB value at the same bar, you need the index of the bar, which is:
Inserted Code
int ixHi = iHighest(NULL,60,MODE_HIGH,5,1);
From this the BB value is calculated:
Inserted Code
double BBval = iBands(NULL,60,20,2,0, MODE_HIGH,MODE_UPPER,  ixHi);
MODE_UPPER is the value for the upper band of the BB and of course ixHi is the bar which is used for the calculation relative to the current bar.

I don't see any obvious errors in the code, but my code seldom works the first time, so be prepared for some debugging.
  • #4
  • Jun 25, 2012 10:55pm Jun 25, 2012 10:55pm
Thank you both for your posts and inputs. Greatly appreciated.

Will check on this tomorrow and let you know. Need some sleep first .

Thanks
  • #5
  • Last Post: Jun 26, 2012 6:34am Jun 26, 2012 6:34am
Quoting CodeMeister
I guess nobody feels like taking this one, so I will.

I am not going to produce working code, but rather explain how to approach the problem.

Right now you have the High value you desire. In order to get the BB value at the same bar, you need the index of the bar, which is:
Inserted Code
int ixHi = iHighest(NULL,60,MODE_HIGH,5,1);
From this the BB value is calculated:
Inserted Code
double BBval = iBands(NULL,60,20,2,0, MODE_HIGH,MODE_UPPER,  ixHi);
MODE_UPPER is the value for the upper band of the BB and of course ixHi is the bar which is...

Your code worked nicely. I am putting this to use. Very simple and understandable. Only thing; I had to change the following to

Inserted Code
double BBval = iBands(NULL,60,20,2,0, [color="Blue"]PRICE_CLOSE[/color],MODE_UPPER,  ixHi);

The PRICE_CLOSE returns the correct BBands value any given time also on the current bar. MODE_HIGH returned higher value, even on current bar with as much as 8 - 10 pips.


Thanks for solving my problem,
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