NormalizeDouble

#1
First Post: Feb 11, 2011 6:39pm Feb 11, 2011 6:39pm

TheForexNerd
| Joined Aug 2010 | Status: Trader | 33 Posts

I did a search through other issues and thought this might be something new.

The EA I am developing is gold except for this one issue.

--//

double Low = NormalizeDouble(iLow(NULL, 0, 1), 5);
Comment(" Current Low is ", Low);

--//

The output is expected as a five-digit price though only comes out as four-digit i.e. 1.23456 is only represented by 1.2345. I thought I might have something set incorrectly in my current code therefore opened a new EA with nothing but this code in the EA. It still comes up with the same four-digit price.

Ideas?

#2
Feb 11, 2011 6:43pm Feb 11, 2011 6:43pm

TheForexNerd
| Joined Aug 2010 | Status: Trader | 33 Posts

I already have considered that if iLow only picks up four-digits that it will not create the last digit expected as a five-digit. Therefore, I am looking to understand how it picks up that fifth digit.

#3
Feb 11, 2011 7:02pm Feb 11, 2011 7:02pm

TheForexNerd
| Joined Aug 2010 | Status: Trader | 33 Posts

Oops...

Low is not actually the variable I am using... Consider that I am actually using CurrentLow to represent the low of the most recent completed candle.

It actually reads...

--//

double CurrentLow = NormalizeDouble(iLow(NULL, 0, 1), 5);

--//

#4
Feb 11, 2011 7:26pm Feb 11, 2011 7:26pm

TheForexNerd
| Joined Aug 2010 | Status: Trader | 33 Posts

I understand the DoubleToStr to show 1.23456, however, I am looking for the variable CurrentLow which is 1.2345 to show up as 1.23456 using NormalizeDouble.

--// Converts CurrentLow from 1.2345 to 1.23456
double CurrentLow = iLow(NULL, 0, 1);
Comment(" Current Low is ", DoubleToStr( CurrentLow, Digits ));

--//Should convert mathematically from 1.2345 to 1.23456, but stays 1.2345
double CurrentLow = NormalizeDouble(iLow(NULL, 0, 1), 5);

I tried also...

--//Should convert mathematically from 1.2345 to 1.23456, but stays 1.2345
double CurrentLow = NormalizeDouble(iLow(NULL, 0, 1), Digits);

--//Should convert mathematically from 1.2345 to 1.23456, but stays 1.2345
double CurrentLow = NormalizeDouble(iLow(NULL, 0, 1), MODE_DIGITS);

So I am missing something here...

#5
Feb 11, 2011 7:50pm Feb 11, 2011 7:50pm

zznbrm
Joined Jul 2008 | Status: Trader | 878 Posts

By "show up as", I assume you mean be displayed or printed somewhere (Experts tab, chart comment, etc).

If the variable CurrentLow has the value 1.2345, then it can never show up as 1.23456. It can show up as 1.2345 or 1.23450 or 1.234500, but it can never show up as 1.23456.

Quoting TheForexNerd

Disliked

I understand the DoubleToStr to show 1.23456, however, I am looking for the variable CurrentLow which is 1.2345 to show up as 1.23456 using NormalizeDouble.

--// Converts CurrentLow from 1.2345 to 1.23456
double CurrentLow = iLow(NULL, 0, 1);
Comment(" Current Low is ", DoubleToStr( CurrentLow, Digits ));

--//Should convert mathematically from 1.2345 to 1.23456, but stays 1.2345
double CurrentLow = NormalizeDouble(iLow(NULL, 0, 1), 5);

I tried also...

--//Should convert mathematically from 1.2345 to 1.23456, but stays 1.2345
double CurrentLow...

Ignored

#6
Feb 11, 2011 8:09pm Feb 11, 2011 8:09pm

TheForexNerd
| Joined Aug 2010 | Status: Trader | 33 Posts

In the case of a five-digit format the iLow should at least indicate a five decimal point price as it does elsewhere such as the Open High Low Close.

The 1.2345 is simply a representation of four-digit decimal value I am getting. I could restate it as iLow is only giving me a four-digit price where I know a five-digit price is available though not sure how to get the five-digit price out of the code. This is why I am using NormalizeDouble where I am obviously not using it correctly.

I have done it before though cannot quite remember how I did it.

I am probably going to be up late figuring this one out.

#7
Feb 13, 2011 11:18am Feb 13, 2011 11:18am

TheForexNerd
| Joined Aug 2010 | Status: Trader | 33 Posts

I walked away from the code and had some fun out with friends intent on coming back to look at the code today. I am approaching the problem from a different angle this time.

Again, the problem is a given value returned by...

double VAR1 = iLow(NULL, 0, 1);

...should have a five-digit price value such as 1.32547 returned as I am using a five-digit account. Instead, the code is returning a four-digit price i.e. 1.3254. MT4 provides...

NormalizeDouble(double value, int digits);

- OR -

NormalizeDouble(VAR1, 5);

...which should give me 1.32547. No dice. So I thought why am I not getting it? Another person helping me stated if there is no fifth digit then you cannot create one using NormalizeDouble so 1.2345 would merely be 1.23450 after the function. Well...ok...fine.

So I ended up doing this...

double VAR1 = 1.2374652;
double VAR2 = NormalizeDouble(VAR1, 5);

...where I should get 1.23746 right? No! In the IBFX MT4 window, I am getting only 1.2374! Frak!

So now I am wondering why does the MT4 I am working within truncate to only four-digit pricing though everything is represented with five-digit pricing elsewhere?

Thoughts?

#8
Feb 13, 2011 12:18pm Feb 13, 2011 12:18pm

zznbrm
Joined Jul 2008 | Status: Trader | 878 Posts

Quoting TheForexNerd

Disliked

double VAR1 = 1.2374652;
double VAR2 = NormalizeDouble(VAR1, 5);

...where I should get 1.23746 right? No! In the IBFX MT4 window, I am getting only 1.2374! Frak!

Ignored

What line of code did you use to display the value in the IBFX MT4 window?

#9
Feb 13, 2011 12:31pm Feb 13, 2011 12:31pm

TheForexNerd
| Joined Aug 2010 | Status: Trader | 33 Posts

Quoting zznbrm

Disliked

What line of code did you use to display the value in the IBFX MT4 window?

Ignored

double VAR1 = 1.123456879;
CMA = NormalizeDouble(VAR1, 5);
Comment(CMA);

Shows as 1.1235

#10
Feb 13, 2011 12:40pm Feb 13, 2011 12:40pm

zznbrm
Joined Jul 2008 | Status: Trader | 878 Posts

What do you get when you try these alternatives?

Inserted Code

double VAR1 = 1.123456879;
double CMA = NormalizeDouble(VAR1, 5);
Comment(DoubleToStr(CMA,5));

Inserted Code

 
double VAR1 = 1.123456879;
Comment(DoubleToStr(VAR1,5));

#11
Feb 13, 2011 12:52pm Feb 13, 2011 12:52pm

TheForexNerd
| Joined Aug 2010 | Status: Trader | 33 Posts

In those cases the value is displayed correctly though unusable when trying to use the numeric value for something else like an OrderModify().

#12
Last Post: Feb 13, 2011 9:47pm Feb 13, 2011 9:47pm

hayseed
Joined Nov 2006 | Status: Trader | 4,417 Posts

comment and print might not show the complete value as expected ...... that can be confusing.......... but ilow and such will still return correct and useable values with proper digits......

as example, the code below will modify precisely either 2,3,4 or 5 digits..... which ever applies......h

Inserted Code

 
 
int start()
  {
//----
   double high = iHigh(NULL,0,shift);
   double low  = iLow(NULL,0,shift);
 
    for(int i=0;i<OrdersTotal();i++)
 
     {
      if(OrderSelect(i,SELECT_BY_POS,MODE_TRADES)==false) continue;
      if(OrderSymbol()!=Symbol()) continue;
      if(OrderStopLoss() > 0.0)   continue;
 
      if(OrderType()==OP_BUY)
        {
         OrderModify(OrderTicket(),OrderOpenPrice(),low,OrderTakeProfit(),0,Green);
         return(0);
        }
 
 
      if(OrderType()==OP_SELL)
       {
       OrderModify(OrderTicket(),OrderOpenPrice(),high,OrderTakeProfit(),0,Red);
       return(0);
       }
 
      }   
//----
   return(0);
  }

to trade and code, keep both simple... no call to impress....h

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