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EA for gambler system

  • #1
  • First Post: Edited Jul 9, 2008 3:18am Jul 8, 2008 8:04am | Edited Jul 9, 2008 3:18am
I have asked if anyone would make an EA for my system described in http://www.forexfactory.com/showthread.php?t=74793 but I did not get an answer so now I try here in the metatrader forum.

As you can see in the other thread people has used this system with success and earned some money on it. Do we have a skilled programmer here on FF that will make an EA for this system? The EA should do the following.

1. Record the highest opening price for up bars within in the latest 5 bars
2. record the lowest opening price for down bars within the latest 5 bars
3. If a bar close below the highest recorded opening price for an up bar the EA should sell.
4. If a bar close above the lowest recorded opening price for a down bar the EA should buy.
5. If the EA is in profit when the bar is finished the position should be closed.
6. If the EA has bought and a bar close below the opening prize of the bar where the EA bought the position should be closed.
7. If the EA has sold and a bar closes above the opening prize of the bar where the EA bought the EA should close the position.
8. If the EA should be traded on a small timeframe it is probably a good idea to have a time setting.
If slaughterhouses had glass walls, everyone would be a vegetarian!
  • #2
  • Jul 8, 2008 10:10am Jul 8, 2008 10:10am
Gambler180,

Can you rephrase step number 4?

lucidlamp
  • #3
  • Edited 7:41am Jul 9, 2008 12:37am | Edited 7:41am
Quoting lucidlamp
Gambler180,

Can you rephrase step number 4?

lucidlamp
Yes I can.

3. If a bar close below the highest recorded opening price for an up bar within the last 5 bars the EA should sell.
4. If a bar close above the highest recorded opening price for a down within the last 5 bars the EA should buy.

In the picture you can see an example of where the EA should buy. The latest candle has closed above the lowest recorded opening price for a down candle within the last 5 candles so it should buy when the new candle opens.

http://img139.imageshack.us/img139/1476/systemvz2.jpg

If a candle then close below the opening price of the candle where we bought the EA should close the position and sell instead as we have got a new sell signal.
If slaughterhouses had glass walls, everyone would be a vegetarian!
  • #4
  • Jul 9, 2008 3:02am Jul 9, 2008 3:02am
Gambler180,

Quoting Gambler180
2. record the lowest opening price for down bars within the latest 5 bars
4. If the price close above the highest recorded opening price for a down bar the EA should buy.
Number two records the value of the lowest open (down bar) of the last five bars, whereas number four requires buying on the highest open (down bar) of the last five bars.

Since the value required by step four has not been recorded by the EA, how will the EA know what the highest open (down bar) of the last five bars is?

Perhaps number four requires the high open recorded by number one?

Quoting Gambler180
4. If a bar close above the highest recorded opening price for a down within the last 5 bars the EA should buy.

In the picture you can see an example of where the EA should buy. The latest candle has closed above the lowest recorded opening price for a down bar within the last 5 bars so it should buy.
Here number four uses the highest open of the down bars in the last five bars, whereas the sentences afterwards say to use the lowest open of the down bars in the last five bars.

Maybe I am reading this wrong?

lucidlamp
  • #5
  • Jul 9, 2008 3:14am Jul 9, 2008 3:14am
Quoting lucidlamp
Gambler180,



Number two records the value of the lowest open (down bar) of the last five bars, whereas number four requires buying on the highest open (down bar) of the last five bars.

Since the value required by step four has not been recorded by the EA, how will the EA know what the highest open (down bar) of the last five bars is?

Perhaps number four requires the high open recorded by number one?



Here number four uses the highest open of the down bars in the last five bars, whereas the sentences afterwards say to use the lowest open of the down bars in the last five bars.

Maybe I am reading this wrong?

lucidlamp
Sorry. 4. should be If a bar close above the lowest recorded opening price for a down bar the EA should buy. I have also corrected that in the first post now.
If slaughterhouses had glass walls, everyone would be a vegetarian!
  • #6
  • Jul 9, 2008 4:02am Jul 9, 2008 4:02am
Gambler180,

Is this the right count? (bar 2 & 5, we'll say are the same open price)

The close of the bar to the right of bar #1 is compared to the previous 5 bars? And the open of the bar 2 bars to the right of bar #1 is when the position is opened, if a signal is given?

If so, in a situation like this, no position is opened?

Attached Image


lucidlamp
  • #7
  • Jul 9, 2008 4:07am Jul 9, 2008 4:07am
Interesting strategy. I'll try to develop it in an EA someday.

Keep your hands up, and use your pant! - FxMatics
  • #8
  • Edited 6:46am Jul 9, 2008 5:10am | Edited 6:46am
Quoting lucidlamp
Gambler180,

Is this the right count? (bar 2 & 5, we'll say are the same open price)

The close of the bar to the right of bar #1 is compared to the previous 5 bars? And the open of the bar 2 bars to the right of bar #1 is when the position is opened, if a signal is given?

If so, in a situation like this, no position is opened?

Attachment

lucidlamp
Yes thats right
If slaughterhouses had glass walls, everyone would be a vegetarian!
  • #9
  • Jul 9, 2008 6:45am Jul 9, 2008 6:45am
Quoting syanwar
Interesting strategy. I'll try to develop it in an EA someday.

Thanks
If slaughterhouses had glass walls, everyone would be a vegetarian!
  • #10
  • Jul 9, 2008 7:17am Jul 9, 2008 7:17am
Trust me Gambler, I've been trying to code this for awhile. The hard part right now is being able to detect the Lowest/highest of a specific bar class in the last 5 bars.
  • #11
  • Jul 9, 2008 7:39am Jul 9, 2008 7:39am
Quoting Ronald Raygun
Trust me Gambler, I've been trying to code this for awhile. The hard part right now is being able to detect the Lowest/highest of a specific bar class in the last 5 bars.
Maybe someone here can help you. We get more progress much faster if we help each other.
If slaughterhouses had glass walls, everyone would be a vegetarian!
  • #12
  • Jul 9, 2008 7:42am Jul 9, 2008 7:42am
Well, the problem's right there.

The iHighest and iLowest functions work only on consecutive bars unless you can direct them to a different array. I don't know how to create an array of up bars/down bars.

The mathmin/mathmax functions are also worth looking into, but first I need to figure out how to create an array/set of data consisting only of up/down bars.
  • #13
  • Jul 9, 2008 8:09am Jul 9, 2008 8:09am
Is there any progress for the EA development from Ronald or anyone else? Let me take a look at it.

It is better to work on one object rather than make another one.

Beside, I like Ronald coding logic so far. Remind me of my past experiences in some programming fields.
Keep your hands up, and use your pant! - FxMatics
  • #14
  • Jul 9, 2008 8:17am Jul 9, 2008 8:17am
Syanwar,

Once I understand how I can get that specifc bit of logic in code, I can pull the rest of the EA together in about 20 mins. You've probably noticed already that in all my EAs, about 90% of the code is exactly the same.

The past 5 bar highest/lowest part is where I'm stuck.

How can I reliably:

  1. Identify which of the 5 bars are up/down
  2. Determine of the up/down bars which are highest and lowest.

  • #15
  • Edited 4:22pm Jul 9, 2008 8:45am | Edited 4:22pm
Ronald Raygun,

extern int Depth=5; // bar look back.

int start()
{
Print(dOpeningPriceLowest());
Print(dOpeningPriceHighest());
}


double dOpeningPriceHighest()
{
double dHigh[]; // array for holding up bar opens.
int x=0;
for(int i=2;i<=Depth+2;i++) // start 2 bars back...
{
if(Open[i]<Close[i]) // if up bar, then...
{
ArrayResize(dHigh,x+1); // largen array to accept a new value...
dHigh[x]=Open[i]; // put open of up bar into array
x++;
}
}
if(x>0) // if x was advanced array was filled...
{
int z=ArrayMaximum(dHigh,WHOLE_ARRAY,0); // find the max in the array.
return(dHigh[z]);
}
return(0);
}

double dOpeningPriceLowest()
{
double dLow[];
int x=0;
for(int i=2;i<=Depth+2;i++)
{
if(Open[i]>Close[i])
{
ArrayResize(dLow,x+1);
dLow[x]=Open[i];
x++;
}
}
if(x>0)
{
int z=ArrayMinimum(dLow,WHOLE_ARRAY,0);
return(dLow[z]);
}
return(0);
}

Of course an array can be hard coded for the number of values held in it, but this way can expand the array if one wishes to make it less or more than a five bar look-back, for optimization, testing, etc..

I have all functions done, just have to put it all into int start()...

If you want to tackle it Ronald Raygun, I won't post mine. Or post the both for a comparison. always good to see how others interpret coding and ways others do things in metaeditor...
  • #16
  • Jul 9, 2008 8:50am Jul 9, 2008 8:50am
Ronald Raygun,

Of course you don't have to post your work for whatever reason. Sometimes I feel attached to my own work as well...

lucidlamp
  • #17
  • Jul 9, 2008 8:53am Jul 9, 2008 8:53am
Thanks for the example LucidLamp, I still am relatively new to MQL, and programming in general.

Looks like function-based programming and that's something I still need to learn. Any guidelines I should know about when programming functions?

(I'll come up with my own non-function-and-far-more-rigid version)
  • #18
  • Jul 9, 2008 9:23am Jul 9, 2008 9:23am
Done. (That took a little longer than I wanted).
Attached File(s)
File Type: mq4 Gambler's system.mq4   13 KB | 530 downloads
  • #19
  • Jul 9, 2008 9:47am Jul 9, 2008 9:47am
Hi there Gambler!
i've tried to intrepret your funtastic system, the attached code is not an EA yet, but it will plot some arrow to the chart acknowledging the user about when to buy, and when to sell

Please take a look, please tell me if there is something need to be fix, and if it's not goes well with the "RULES"

Regards,
Attached File(s)
File Type: mq4 Gambler5Bar.mq4   3 KB | 560 downloads
-1128 Pips since 6 August 2007
  • #20
  • Jul 9, 2008 11:14am Jul 9, 2008 11:14am
Quoting Ronald Raygun
Done. (That took a little longer than I wanted).
Ronald,
Thanks for being the quickest coder.. I was looking at the code, though i am not as good as yourself. I hope you dont mind me commenting on the code you just posted...I could be wrong though..

a) since you are using a value of 0(zero) for the Shorts on the upbars.. Dont you think this will affect your calculation on the MathMin() function?
b) Line 150 & 151, i think have some typo on the Shorts.
Thanks
Trader101
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