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Changing line color

  • #1
  • First Post: Jun 2, 2007 8:30pm Jun 2, 2007 8:30pm
I wrote a simple oscillator indicator and am trying to make it change color depending on its value. My understanding of how mql works in regard to this things is very limited so any input would be greatly appreciated.
With my limited understanding it seems that any given line plotted can only have one color. If that is true then i would perhaps need to plot 2 lines. One line would be one color and would be plotted when the indicator would have a certain value and the other one would be ploted when that value would be exceeded and would have a different color. If someone could clear this up for me with a little code example i would greatly apreciate it.
Stubbornly persistent
  • #2
  • Jun 4, 2007 6:42am Jun 4, 2007 6:42am
Anyone?
Stubbornly persistent
  • #3
  • Jun 4, 2007 2:23pm Jun 4, 2007 2:23pm
  •  iya
  • | Joined Oct 2006 | Status: always protect yourself | 129 Posts
It works exactly like you said: use two indicator lines with different colors.
As an example you can look at practically any of the multi colored indicators out there.
  • #4
  • Jun 6, 2007 10:03am Jun 6, 2007 10:03am
I have arrived at the conclusion that the only way to have my ind plot 2 colors is to draw it as a histogram.
Here is the code:

Inserted Code
 if (Result>55*Point)
   {
   ExtMapBuffer1[pos]=Result;
   ExtMapBuffer2[pos]=0;
    }
   else
   {
   ExtMapBuffer2[pos]=Result;
   ExtMapBuffer1[pos]=0;
   }
The only other way that i can think of is to have 2 loops - one for each buffer. One of them would be populated when one condition is true and when it is false the loop would terminated and the other loop would start. This however is way over my head. It is not that important but if someone could clarify this for me it would be a great help for my understanding of how MQL works.
Here is a picture with the ind drawn as a line:
Attached Image (click to enlarge)
Click to Enlarge Name: 333.jpg Size: 18 KB
Stubbornly persistent
  • #5
  • Jun 6, 2007 10:04am Jun 6, 2007 10:04am
Here is the histogram version:
Attached Image (click to enlarge)
Click to Enlarge Name: 333.gif Size: 4 KB
Stubbornly persistent
  • #6
  • Jun 6, 2007 11:07am Jun 6, 2007 11:07am
  •  tesla
  • | Joined Oct 2006 | Status: Friendly Neighborhood Programmer | 533 Posts
Quoting sergiu
I have arrived at the conclusion that the only way to have my ind plot 2 colors is to draw it as a histogram.
Here is the code:

Inserted Code
 if (Result>55*Point)
   {
   ExtMapBuffer1[pos]=Result;
   ExtMapBuffer2[pos]=0;
    }
   else
   {
   ExtMapBuffer2[pos]=Result;
   ExtMapBuffer1[pos]=0;
   }
The only other way that i can think of is to have 2 loops - one for each buffer. One of them would be populated when one condition is true and when it is false the loop would terminated and the other loop would start. This however is way over my head. It is not that important but if someone could clarify this for me it would be a great help for my understanding of how MQL works.
Here is a picture with the ind drawn as a line:
The reason you're seeing the lines bottoming out that way is because you're setting the buffers to zero, which is a valid value to "draw". Try setting the buffers to EMPTY_VALUE when you don't want that line to show up.

Inserted Code
 if (Result>55*Point)
   {
   ExtMapBuffer1[pos]=Result;
   ExtMapBuffer2[pos]=EMPTY_VALUE;
    }
   else
   {
   ExtMapBuffer2[pos]=Result;
   ExtMapBuffer1[pos]=EMPTY_VALUE;
   }
But... there's one more thing to consider. You're going to have a gap between the lines where one stops and the other starts. Try simply plotting the first buffer for all values and only plotting the second when the appropriate conditions are met, it will overlay the first and you should get the desired effect. The additional advantage here is that you could always access that first index buffer from an EA and be assured of a valid value.
  • #7
  • Jun 6, 2007 1:10pm Jun 6, 2007 1:10pm
Quoting tesla
The reason you're seeing the lines bottoming out that way is because you're setting the buffers to zero, which is a valid value to "draw". Try setting the buffers to EMPTY_VALUE when you don't want that line to show up.

Inserted Code
 if (Result>55*Point)
   {
   ExtMapBuffer1[pos]=Result;
   ExtMapBuffer2[pos]=EMPTY_VALUE;
    }
   else
   {
   ExtMapBuffer2[pos]=Result;
   ExtMapBuffer1[pos]=EMPTY_VALUE;
   }
But... there's one more thing to consider. You're going to have a gap between the lines where one stops and the other starts. Try simply plotting the first buffer for all values and only plotting the second when the appropriate conditions are met, it will overlay the first and you should get the desired effect. The additional advantage here is that you could always access that first index buffer from an EA and be assured of a valid value.
Thanks a lot tesla!
Stubbornly persistent
  • #8
  • Last Post: Jun 6, 2007 1:25pm Jun 6, 2007 1:25pm
Quoting tesla
The reason you're seeing the lines bottoming out that way is because you're setting the buffers to zero, which is a valid value to "draw". Try setting the buffers to EMPTY_VALUE when you don't want that line to show up.

Inserted Code
 if (Result>55*Point)
   {
   ExtMapBuffer1[pos]=Result;
   ExtMapBuffer2[pos]=EMPTY_VALUE;
    }
   else
   {
   ExtMapBuffer2[pos]=Result;
   ExtMapBuffer1[pos]=EMPTY_VALUE;
   }
But... there's one more thing to consider. You're going to have a gap between the lines where one stops and the other starts. Try simply plotting the first buffer for all values and only plotting the second when the appropriate conditions are met, it will overlay the first and you should get the desired effect. The additional advantage here is that you could always access that first index buffer from an EA and be assured of a valid value.
A couple of questions if i may...
Since there is going to be one line drawn on top of another line the conditional buffer would have to be drawn second in order for the color to be visible, am i correct?
Are the buffers drawn in the same order in which they are indexed(ie SetIndex(0.... drawn first SetIndex(1... drawn second etc...?
Stubbornly persistent
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