Need help to get result in % instead of difference in number

Quoting john.smith4x

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Can someone please help me to amend this code to give me result in % instead of a number? int DiFF = (Close[Shift] - MA)/Point; (100[0] - 120) gives me a result of -20 but I need in % (example -20%) Please help. Thank you.

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double DiFF = ((Close[Shift] - MA)/Point) / Close[Shift]*100;

Quoting john.smith4x

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Thank you so much, this works but gives me a round number, for example 1, 2, 3 ... I want results like 1.25% (instead of 1 or 2). How do I do it? Thanks again... your help is much appreciated.

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Quoting john.smith4x

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I got this working...thank you so so much.

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