How to get the Shift of 1st Group in a Loop | Forex Factory

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How to get the Shift of 1st Group in a Loop

  • #1
  • First Post: Edited 3:15am Aug 26, 2021 2:37am | Edited 3:15am
Hi coders, I cannot solve a situation to get the shift of first group that meeting the "three straight red bars" from bar100 to bar1.

Kindly have a look at my codes and picture, I want to get the redSf=26 and stop there, and will not carry on to loop till redSf=1.

Inserted Code
   int redSf=0;
   for(int i=100; i>=1; i--) {
      double aa=iOpen(symbol,15,i)>iClose(symbol,15,i);
      double bb=iOpen(symbol,15,i+1)>iClose(symbol,15,i+1);
      double cc=iOpen(symbol,15,i+2)>iClose(symbol,15,i+2);
   if(aa && bb && cc) redSf=i;
   }

Kindly provide your correction codes and ensure that if there is no such "three straight red bars" for the last 100 bars and will not cause any looping error. Thanks
Attached Image (click to enlarge)
Click to Enlarge Name: 3RedBars.png Size: 18 KB
  • #2
  • Edited Aug 27, 2021 1:47am Aug 26, 2021 7:17am | Edited Aug 27, 2021 1:47am
The break operator terminates the execution of the nearest nested outward switch, while, do-while or for operator.

Inserted Code
if(aa && bb && cc) { redSf=i; break; }

Also, just for clarity, I would change aa, bb, cc to be of type bool type rather than double.

Regards, Paul.
  • #3
  • Last Post: Aug 26, 2021 8:14am Aug 26, 2021 8:14am
Quoting pah
The break operator terminates the execution of the nearest nested outward switch, while, do-while or for operator. if(aa && bb && cc) { redSf=i;...
Thanks so much Paul, will test, regards ...
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