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Function inquiry

  • #1
  • First Post: Apr 11, 2021 8:08am Apr 11, 2021 8:08am
Inserted Code
double DemLow(int cnt, int sh)
  {
   if(Low[cnt]<=Low[cnt+sh] && Low[cnt]<Low[cnt-sh])
     {
      if(sh>1)
         return(DemLow(cnt,sh-1));
      else
         return(Low[cnt]);
     }
   else
      return(0);
  }

I have 2 questions please,

1- for the array Low[cnt-sh], what if the value of sh is greater than the value of cnt , so that will make the element of low array will negative. so what will be the out come of this function ? will it return zero or it wont operate?

2-
Inserted Code
 if(Low[cnt]<=Low[cnt+sh] && Low[cnt]<Low[cnt-sh])
     {
      if(sh>1)
         return(DemLow(cnt,sh-1));
      else
         return(Low[cnt]);
I want to make sure that I understand these lines correctly, can I can consider this as loop in this function that it will check the condition of DemLow as long as " sh" is greater than 1, and it will do this until the "sh" is equal to one then it will exit by giving the return value of Low[cnt]?

thanks in advance
  • #2
  • Apr 11, 2021 9:07am Apr 11, 2021 9:07am
1. You cannot have a negative index for an array. The program will terminate with an array out of range error.
2. In theory, your understanding is correct, however, looking at the code in Q1(and assuming the code is Q2 is a subset of Q1 code, as it appears to be), DemLow just keeps on calling itself(which is a bad bad idea), and I don't see where the value of sh is going to change.
  • #3
  • Last Post: Apr 11, 2021 9:16am Apr 11, 2021 9:16am
Quoting kennyhubbard
however, looking at the code in Q1(and assuming the code is Q2 is a subset of Q1 code, as it appears to be), DemLow just keeps on calling itself(which is a bad bad idea), and I don't see where the value of sh is going to change.
Yes Q2 is subset of Q1

and the value of sh is going to be reduced in this subset of Q2
return(DemLow(cnt,sh-1));

thank you so much
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