Last two trades AUDUSD in Trade-Explorer are testing the algo to get gracefully (?) out of an hedge.
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Disliked@ gg53 very good, I have a doubt that, with respect to implementing "monty hall" in "next bar". I try to find the similarity with fractal pattern match: 1 - [Actuall bar] 2 - [actuall bar + 0] 3 - [actuall bar + 1] actuall bar = sequence from last 12 bar There may be "Monty Hall" a pattern of greater length of 3? That is my question thank you very muchIgnored
DislikedCreating SET2: From the same historical data on M5 (2011-2012) we now create our ZZ and Fractals dataset. we apply 2 standard MT4 indicators, Fractals and ZigZag (13,8,5) on that historical data. An MT4 script that writes the results to CSV will be posted later on. For EACH ZZ leg we store its fractal sequence and the total length (bar count) of that ZZ leg. UP fractal is marked as "1". Down fractal is marked as "0". So a record of each ZZ leg should look something like this: {10011} - fractal sequence within that ZZ leg 12 - total length (bar count)...Ignored
Disliked{quote} This is a really interesting work in progress. When referring to "Total length (bar count)" are you referring to the number of candles within the zz leg?Ignored
Dislikedhi everyone, im still far behind of gg53's indicator because of some contradictions. the logic is : "current fractal pattern" "current length" "current +1 bar (which is the next bar) in opposite direction" right? but if you look at the attatched picture, you can see: fractal pattern ----- length [] ----- 4 (the red circle in the picture) [] ----- 1 (the blue circle in the picture) this means that the prediction is confirmed for "null fractal". i can see many "null fractal prediction" at gg53's pictures. my understanding is that if there is no fractal,...Ignored
DislikedLast two trades AUDUSD in Trade-Explorer are testing the algo to get gracefully (?) out of an hedge. G.Ignored
Disliked{quote} This is a really interesting work in progress. When referring to "Total length (bar count)" are you referring to the number of candles within the zz leg?Ignored
Disliked{quote} Jim, It has been explained that there will be turning points where fractals have not shown up yet. Remember, we are trying to predict a turning point (fractal). So, if the previous fractal was a low fractal (signal as shown in the screenshot), you could reasonably say that a high fractal is next. So you would really be searching for a "1". In my database a "1" can occur (high probability) at bar 6. So using -3 and +3, we go to "next bar" after 3 bars (G's database may be different). So, in this case, a pattern match occurred for a length...Ignored
Disliked{quote} thank you carl! so, you mean that we predict the current bar to be a fractal or not? and current fractal pattern +"1" or +"0" to be the turning point? (depending on upleg or downleg) or is it just an exception when we have no fractal? if you look at gg53's post: http://www.forexfactory.com/showthread.php?p=7205217#post7205217 you can not predict until bar 8. so confusing... by the way, how about the blue circle in my last post, which is zero fractal & one down bar ? from my database, fractal "1" occurs at bar 5 (highest...Ignored
Disliked{quote} thank you carl! so, you mean that we predict the current bar to be a fractal or not? and current fractal pattern +"1" or +"0" to be the turning point? (depending on upleg or downleg) or is it just an exception when we have no fractal? if you look at gg53's post: http://www.forexfactory.com/showthread.php?p=7205217#post7205217 you can not predict until bar 8. so confusing... by the way, how about the blue circle in my last post, which is zero fractal & one down bar ? from my database, fractal "1" occurs at bar 5 (highest...Ignored
Dislikedmy algorithm will search for a [1] high fractal and determine the length, even though no fractals have occurred yet (because they would be 2 bars late).Ignored
Dislikedhuub and carl, thank you very much! too many different interpretations to understand, especially for non english native speaker. but you both seems right. and i have just found this post from ultimate truth thread. http://www.forexfactory.com/showthread.php?p=7162626#post7162626 so if we are at upleg and current pattern is zero fractal or fractal pattern ending with "0", we have to add "1" and compare this pattern to longer pattern. if our current fractal pattern is ending with "1", we compare this with longer pattern, right? and how...Ignored
Disliked{quote} I've been doing it both ways like Carl is doing and without adding artifically the "missing" fractal. My explanation is that at any given point we are looking at 3 patterns - current, current+1 and current+0. Therefore, if current pattern is NoN, longer patterns are 1 and 0. So, patterns containing only one fractal are still used. There's one "if" of course - that is if the longer pattern (which comes up as the most probable) gets passed on to length matching. I understand G is currently using only current pattern, not longer ones, in the...Ignored
Disliked{quote} Hi Jim, There are several rules for sure the most will be true but not all the time. A possible way to find out, i'm trying just now, is to work backwards. If you take your posted chart form GG on this page , just take a swing point. For sure you are in step 3 of the algo. Take from that point backwards the barstring for f.i. the last 20 bars. Test your own step 3 algo, you know for this situation, you must have an opposite bar prediction, otherwise you have to look at your algo. Now go one bar back, do the algo again, you must now have...Ignored