Disliked{quote} No,language is mql here. doesnt matter your english level. if you dont know exactly about concepts of two dimentional arrays, you dont understand my posts as below {quote}Ignored
Please Do Not PM Me With Coding Enquiries
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Disliked{quote} No,language is mql here. doesnt matter your english level. if you dont know exactly about concepts of two dimentional arrays, you dont understand my posts as below {quote}Ignored
Disliked{quote} No,language is mql here. doesnt matter your english level. if you dont know exactly about concepts of two dimentional arrays, you dont understand my posts as below {quote}Ignored
Dislikedthis code will do what you want it sorts each of the element columns descending as I said not a very efficient way of storing the data as it has to 1) copy 500x28 items = 14,000 copies between different arrays and array dimensions 2) sort 28 items 500 times 3) then again copy 500x28 items = 14,000 copies between different arrays and array dimensions {file}Ignored
Disliked{quote} Ok,it is ok, i got it, Thanks. i have the logic of how sort two dimentional arrarys. After all self explanatory. But i have one simple question. if i explain well and you answer that it would be double ok. Que. is;i have string array as you code pairs[28] . This array consist of 28 pairs. For example i want to put this array as variable into the iclose() function. Such as; for(int i,i=0,i<500, i++) { For(int k,k=0,k,<28,k++) { iclose( pair[k],0,i) } } how i code this string variable? With q. marks or using + ? i wan to code symbol()...Ignored
Disliked{quote} of course you have the logic I gave it to you and if it is so bloody self explanatory then why did you need help... you really are the most ungrateful person I have come across on these forums. as for your latest question just put the array reference in, no quotes etc, it's not rocket science surely you would have tried that.Ignored
Disliked{quote} no you didnt give me any logic!! You cant. Be smart body. You show some codes, and thank you. Only this code "SortArray[Ref] = BigArray[Ref][Element]" enough for me.Ignored