if you can apply your prediction to ordinary ema, you can get the associated close value with a simple algebra.
suppose N = ema period
SF = smooth factor = 2/(N+1)
ema formula:
current_ema = last_ema + SF*(current_close - last_ema)
future_ema = current_ema + SF*(future_close - current_ema)
future_close = (future_ema - current_ema)/SF + current_ema
future_close = future_ema/SF + current_ema*(1-1/SF)
giving the value of current ema, you can calculated future close.
pls note, the above formula show that prediction error of future ema will be more significant at smaller SF (hence longer ema period), because that 1/SF factor.
for example:
for ema period = 9, SF = 0.2. error of future ema will be 1/0.2 = 5 times larger
for ema period = 19, SF = 0.1. error of future ema will be 1/0.1 = 10 times larger
suppose N = ema period
SF = smooth factor = 2/(N+1)
ema formula:
current_ema = last_ema + SF*(current_close - last_ema)
future_ema = current_ema + SF*(future_close - current_ema)
future_close = (future_ema - current_ema)/SF + current_ema
future_close = future_ema/SF + current_ema*(1-1/SF)
giving the value of current ema, you can calculated future close.
pls note, the above formula show that prediction error of future ema will be more significant at smaller SF (hence longer ema period), because that 1/SF factor.
for example:
for ema period = 9, SF = 0.2. error of future ema will be 1/0.2 = 5 times larger
for ema period = 19, SF = 0.1. error of future ema will be 1/0.1 = 10 times larger