DislikedIs the day over for the EUR\USD to go down ? "After the Good USD news"Ignored
- Post #923,501
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- Sep 12, 2014 11:22am Sep 12, 2014 11:22am
- Joined Sep 2012 | Status: Member | 2,812 Posts
- Post #923,504
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- Sep 12, 2014 11:25am Sep 12, 2014 11:25am
- Joined Feb 2012 | Status: Giving earnings to the wife | 1,193 Posts
I don't even have a cool signature
- Post #923,506
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- Sep 12, 2014 11:27am Sep 12, 2014 11:27am
the true currencies here is patience and react precisely
- Post #923,507
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- Sep 12, 2014 11:27am Sep 12, 2014 11:27am
I'm tired of making many samll GREEN pips, then one BIG red wash them all.
- Post #923,508
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- Sep 12, 2014 11:30am Sep 12, 2014 11:30am
the true currencies here is patience and react precisely
- Post #923,510
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- Sep 12, 2014 11:31am Sep 12, 2014 11:31am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c
- Post #923,511
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- Sep 12, 2014 11:33am Sep 12, 2014 11:33am
- Joined Feb 2012 | Status: Giving earnings to the wife | 1,193 Posts
I don't even have a cool signature
- Post #923,512
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- Sep 12, 2014 11:34am Sep 12, 2014 11:34am
- | Membership Revoked | Joined Jun 2007 | 3,782 Posts
- Post #923,513
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- Sep 12, 2014 11:34am Sep 12, 2014 11:34am
- Joined Sep 2012 | Status: Member | 2,812 Posts
- Post #923,514
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- Sep 12, 2014 11:37am Sep 12, 2014 11:37am
- Joined Feb 2012 | Status: Giving earnings to the wife | 1,193 Posts
I don't even have a cool signature
- Post #923,515
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- Sep 12, 2014 11:37am Sep 12, 2014 11:37am
- Joined Sep 2012 | Status: Member | 2,812 Posts
- Post #923,516
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- Sep 12, 2014 11:39am Sep 12, 2014 11:39am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c
- Post #923,517
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- Sep 12, 2014 11:40am Sep 12, 2014 11:40am
- | Commercial Member | Joined Aug 2014 | 1,024 Posts
While knowledge speak up, the wisdom listen down
- Post #923,518
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- Sep 12, 2014 11:41am Sep 12, 2014 11:41am
- | Membership Revoked | Joined Jun 2007 | 3,782 Posts
- Post #923,519
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- Sep 12, 2014 11:43am Sep 12, 2014 11:43am
- | Commercial Member | Joined Feb 2010 | 13,255 Posts
- Post #923,520
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- Sep 12, 2014 11:45am Sep 12, 2014 11:45am
- Joined Dec 2013 | Status: Member | 2,118 Posts
f(z)=z2+c