f(z)=z2+c
- #963,841
- Feb 25, 2015 9:28am Feb 25, 2015 9:28am
- Joined Dec 2013 | Status: Trader | 2,141 Posts
f(z)=z2+c
- #963,843
- Feb 25, 2015 9:31am Feb 25, 2015 9:31am
- Joined Dec 2013 | Status: Trader | 2,141 Posts
f(z)=z2+c
- #963,846
- Feb 25, 2015 9:42am Feb 25, 2015 9:42am
- Joined Sep 2014 | Status: Don't make me use this! | 1,214 Posts
- #963,848
- Feb 25, 2015 9:53am Feb 25, 2015 9:53am
- Joined Apr 2013 | Status: I'm learnding! | 8,973 Posts
- #963,854
- Feb 25, 2015 10:27am Feb 25, 2015 10:27am
- Joined May 2014 | Status: From1toMillion | 9,473 Posts | Online Now
Everyone can see the chart, but only a few can actually read it.
- #963,855
- Feb 25, 2015 10:28am Feb 25, 2015 10:28am
- Joined Apr 2013 | Status: I'm learnding! | 8,973 Posts
- #963,856
- Feb 25, 2015 10:29am Feb 25, 2015 10:29am
- Joined Jul 2009 | Status: Winter is coming. Ask Kondratieff. | 8,196 Posts
"I know one thing, that I know nothing." Sokrates
- #963,857
- Feb 25, 2015 10:31am Feb 25, 2015 10:31am
- Joined Sep 2014 | Status: Don't make me use this! | 1,214 Posts
- #963,858
- Feb 25, 2015 10:31am Feb 25, 2015 10:31am
- Joined May 2014 | Status: From1toMillion | 9,473 Posts | Online Now
Everyone can see the chart, but only a few can actually read it.