I don't even have a cool signature
- #919,401
- Aug 26, 2014 5:19am Aug 26, 2014 5:19am
- | Joined Feb 2012 | Status: Giving earnings to the wife | 1,193 Posts
I don't even have a cool signature
- #919,403
- Aug 26, 2014 5:28am Aug 26, 2014 5:28am
- Joined Aug 2009 | Status: Trader | 12,448 Posts
If you are new to Forex? Say Goodbye to your account!!
- #919,404
- Aug 26, 2014 5:32am Aug 26, 2014 5:32am
- | Joined Jun 2014 | Status: Full time retard | 1,561 Posts
Why sell the bottoms when you can buy the tops...
- #919,405
- Aug 26, 2014 5:32am Aug 26, 2014 5:32am
- | Joined Feb 2012 | Status: Giving earnings to the wife | 1,193 Posts
I don't even have a cool signature
- #919,407
- Aug 26, 2014 5:35am Aug 26, 2014 5:35am
- | Joined Feb 2012 | Status: Giving earnings to the wife | 1,193 Posts
I don't even have a cool signature
- #919,409
- Aug 26, 2014 5:38am Aug 26, 2014 5:38am
- | Joined Jun 2014 | Status: Full time retard | 1,561 Posts
Why sell the bottoms when you can buy the tops...
- #919,410
- Aug 26, 2014 5:42am Aug 26, 2014 5:42am
- | Joined Feb 2012 | Status: Giving earnings to the wife | 1,193 Posts
I don't even have a cool signature
- #919,411
- Aug 26, 2014 5:43am Aug 26, 2014 5:43am
- Joined Dec 2013 | Status: Trader | 2,141 Posts
f(z)=z2+c
- #919,413
- Aug 26, 2014 5:45am Aug 26, 2014 5:45am
- Joined Aug 2009 | Status: Trader | 12,448 Posts
If you are new to Forex? Say Goodbye to your account!!
- #919,414
- Aug 26, 2014 5:45am Aug 26, 2014 5:45am
- | Joined Jun 2014 | Status: Full time retard | 1,561 Posts
Why sell the bottoms when you can buy the tops...
- #919,416
- Aug 26, 2014 5:46am Aug 26, 2014 5:46am
- Joined Dec 2013 | Status: Trader | 2,141 Posts
f(z)=z2+c
- #919,417
- Aug 26, 2014 5:47am Aug 26, 2014 5:47am
- Joined Aug 2009 | Status: Trader | 12,448 Posts
If you are new to Forex? Say Goodbye to your account!!
- #919,418
- Aug 26, 2014 5:47am Aug 26, 2014 5:47am
- | Joined Feb 2012 | Status: Giving earnings to the wife | 1,193 Posts
I don't even have a cool signature
- #919,419
- Aug 26, 2014 5:50am Aug 26, 2014 5:50am
- Joined Dec 2013 | Status: Trader | 2,141 Posts
f(z)=z2+c