# Line slope calculator 4x+y=17

**Straight line given by points A[3; 5] and B[4; 1]**

## Calculation:

**Slope-intercept form of line:**y = -4x+17

**Canonical form of the line equation:**4x+y-17 = 0

**Parametric form of the line equation:**

x = t+3

y = -4t+5 ; t ∈ R

**Slope:**m = -4

**Slope angle of line: φ =**-75°57'50″ = -1.3258 rad

**X intercept:**x

_{0}= 4.25

**Y intercept:**y

_{0}= q = 17

**Distance line from the origin:**d

_{0}= 4.1231

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(1; -4)

**Normal vector: n =**(4; 1)

**Midpoint of the segment AB: M =**[3.5; 3]

**Perpendicular Bisector equation:**x-4y+8.5 = 0

**Vector OA = (3; 5) ; |OA| = 5.831**

**Vector OB = (4; 1) ; |OB| = 4.1231**

**Scalar product OA .OB = 17**

**Angle ∠ AOB = 45° = 0.7854 rad**